A beautiful proof about Mersenne primes
Theorem: 2n - 1 cannot be prime if n is composite.
Lemma: cn - 1 can be written as (c - 1)(cn-1 + … + c1 + 1).
The proof for the lemma is simple. You end up subtracting
c^n + c^{n-1} + ... + c - c^{n-1} + ... + c + 1 ------------------------------------ c^n - 1
So if n can be written as ab where both a > 1 and b > 1, then
2^{ab} - 1 = (2^a)^b - 1 = (2^a - 1)((2^a)^{b-1} + (2^a)^{b-2} + ... + 1)
So we have (2a - 1) as a divisor.
A stronger theorem is: Suppose c > 1 and n > 1, and cn - 1 is a prime, then c = 2 and n is a prime.
See this handout for this and other proofs.
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